#Workdone calculator how to
#Workdone calculator plus

So i'll just take that my calculator and i end up with 4420.5, so the selling price is this. Working Days Calculator: Business Days Between Two Dates.

#Workdone calculator plus

When we calculate our selling price, it's the original price, i should say the cost plus the profit, so the cost is 290 and the profit is 45 percent of 290 point. So all we need to do that is say: 45 percent, as a decimal is. So what we're saying by cost is what it costs the tree farm, so we want to then add on a 45 percent profit and find out what they sell it for okay. It is sold with a 45 percent profitand we're trying to find the original price or what the selling price is sorry. 2- tells you that the cost of a bag of almonds is 290 or or 290 point yea. So the boys end up with 400 point, and that completes your first question. We could solve that same proportion by putting a 25 there, but we might as well just subtract the 240 from the 640 and you could get it that way as well. Now the boys we could set up a proportion the same way.

So the girls make 240 or so we'll say that girls be re to 40 point. We cross multiply so you're gonna end up with 40 times g equals 15 times 640, which is 9600 and now we'll divide by 40 point. Then we'll just put g up here for girls and to solve this. The ratio of trees planted for girls will be 15 to a total of 40 trot and they need to do that to the total, because i'm going to set it equal to a ratio that has a total of 640 point. So i'm gonna first determine the girls payment. So what we want to do here is determine you're told that the boys and girls need to be paid at the same ratio as the number of trees they planted. 1, which is saying that girls plant 15 trees at this nut farm and the boys plant 25 trees at the nut farm and they are paid total 640- are all right. Friction is a good example - an object pushed over a short, direct path will feel the effects of friction for a short while, while an object pushed over a long, meandering path to the same ending location will feel more friction overall.All right in your question, you have question 1.1. Note that non-conservative forces are forces whose power to affect an object's acceleration depends on the path taken by the object.In this case, the train's final energy is TME i + W nc = 100 + 86.6 = 186.6 joules. Weight of member (mass)× (gravitational acceleration) (400 kg)× (9.81 m/s 2) 3,924 N. Since the force in the problem is pulling the train in the direction that it's already traveling, it's positive. How much work must be done on the member to move it from the ground to the 20th floor Solution: 1.) Force required to lift weight of member. For instance, for the example problem in the two steps above, let's say that the train initially had a total mechanical energy of 100 joules.Note that both energy variables can be found with the formula (½)mv 2 where m = mass and v = volume. In this formula, if the force pushes with the direction of motion, it's positive, and if it pushes against it, it's negative. In the formula above, TME i = the initial total mechanical energy within the system, TME f = the final total mechanical energy within the system, and W nc = the work performed on the system due to non-conservative forces. Work can also be used to find the energy held within a system. Use the formula TME i + W nc = TME f to find the mechanical energy in a system. In the next few steps, we'll use this information to help find the work done on the object.

In this case, both the force vector and the direction of the train's motion point the same way - forward. Say that a toy train car is being pulled directly forward by the train in front of it. To make this process easy to understand, let's follow along with an example problem.

#Workdone calculator how to

For information on how to find the work when these things don't have the same direction, see below. In this section, however, we'll deal with situations in which the force and the object's displacement do have the same direction. Keep in mind that objects don't always move in line with the force being applied to them - for instance, if you pull a small wagon by its handle, you're applying a diagonal force (assuming you're taller than the wagon) to move it forward. To start, it's important to first be able to identify both the direction the object is moving in and the direction from which force is being applied. Find the direction of the force vector and the direction of motion.